2) In a courtyard, 1.4 metre diameter and 10 m
deep well was dug. The excavated soil was
spread on the cuboid shape of c

Question

2) In a courtyard, 1.4 metre diameter and 10 m
deep well was dug. The excavated soil was
spread on the cuboid shape of courtyard. The
length and width of the courtyard is 55 metre
and 14 metre respectively. So find the
thickness of that spread soil.​

in progress 0
Genesis 4 months 2021-08-01T09:29:21+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-01T09:30:24+00:00

    Given :  In a courtyard, 1.4 metre diameter and 10 m deep well was dug. The excavated soil was spread on the cuboid shape of courtyard. The

    length and width of the courtyard is 55 metre and 14 metre respectively.  

    To find : the thickness of that spread soil.​

    Solution:

    1.4 metre diameter and 10 m deep well was dug.

    Volume of soil extracted = πR²h

    R = 1.4/2 = 0.7

    h = 10 m

    π = 22/7

    => Volume of soil extracted =  (22/7) * (0.7)² * 10

    = 22 * 0.1 * 0.7 * 10

    = 15.4  m³

    Volume of cuboid = 55 x 14 x thickness

    55 x 14 x thickness  =  15.4

    =>  55     x thickness  =  1.1

    => thickness  =  1.1/55  m

    => thickness = 110/55  cm

    =>  thickness = 2 cm

    thickness of that spread soil.​ = 2  cm

    Learn More:

    possible value of radius is?​

    brainly.in/question/23926217

    in a solid hemisphere the circumference of circular base

    brainly.in/question/23927955

    0
    2021-08-01T09:30:40+00:00

    Solution :

    Let us assume that, the thickness of that spread soil is x m .

    so,

    → Volume of soil dug out = Volume of courtyard in the shape of cuboid .

    we know that,

    • Volume of cylinder = π * (radius)² * height(depth) .
    • Volume of cuboid = Length * Breadth * height(thickness) .
    • Radius = Diameter / 2 .

    putting given values we get,

    → (22/7) * (1.4/2)² * 10 = 55 * 14 * x

    → (22/7) * (0.7)² * 10 = 55 * 14 * x

    → 22 * 0.1 * 0.7 * 10 = 55 * 14 * x

    → 2.2 * 7 = 55 * 14 * x

    → 2.2 = 55 * 2 * x

    → 110x = 2.2

    → x = (22/1100)

    → x = (2/100)

    → x = 0.02 m or 2 cm. (Ans.)

    Hence, the thickness of that spread soil is 0.02 m (2cm) .

    Learn more :-

    from a solid cylinder whose height is 3.6 cm and diameter 2.1 CM a conical cavity of the same height and the same diamet…

    https://brainly.in/question/24336372

    A hemisphere of radius 21 cm is completely filled with milk. There is a hole in

    the bottom whose radius is 0.1 cm. If ra…

    https://brainly.in/question/25349591

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )