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Question 1:
tane
tan6+4 tan 0+3
=..
1
+
2(tan 0+3)
5
2(tan 0+1
1
(tan 6+3)

By Peyton

Question 1:
tane
tan6+4 tan 0+3
=..
1
+
2(tan 0+3)
5
2(tan 0+1
1
(tan 6+3)
5
(tan 0+1)
3
+
4(tan 0+3)
5
(tan +1
3
2(tan 0+3
1
2(tan +1​

About the author
Peyton

Find the positive difference between the product of 78 and 36 and their sum

Integer type questions :
1. 2xy + 6xz = P(xy + 3xz), then p =how much​

1 thought on “Question 1:<br />tane<br />tan6+4 tan 0+3<br />=..<br />1<br />+<br />2(tan 0+3)<br />5<br />2(tan 0+1<br />1<br />(tan 6+3)<br />”

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