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Answer: n3 – n = n(n2 – 1) = n(n+1)(n – 1) = (n – 1)n(n+1) = product of three consecutive positive integers. Now, we have to show that the product of three consecutive positive integers is divisible by 6. We know that any positive integer n is of the form 3q, 3q + 1 or 3q + 2 for some positive integer q. Now three consecutive positive integers are n, n + 1, n + 2. Reply
Answer:
n3 – n = n(n2 – 1) = n(n+1)(n – 1) = (n – 1)n(n+1) = product of three consecutive positive integers.
Now, we have to show that the product of three consecutive positive integers is divisible by 6.
We know that any positive integer n is of the form 3q, 3q + 1 or 3q + 2 for some positive integer q.
Now three consecutive positive integers are n, n + 1, n + 2.