Contact Style About

Q3. The four angles of the quadrilateral are equal. Find measure of each angle
Q4. The base of parallelogram is 12 cm and its

By Charlie

Q3. The four angles of the quadrilateral are equal. Find measure of each angle
Q4. The base of parallelogram is 12 cm and its height is 18 cm. Find its area.
Q5. Find probability of getting a 4 by rolling a fair dice.​

About the author
Charlie

families
in a village
Correspondence with the number of children are given below:
1
2
3
4
No of

if x^2-(a+4)x-18=0 is -3 then find the value of a

don’t spam​

2 thoughts on “Q3. The four angles of the quadrilateral are equal. Find measure of each angle<br />Q4. The base of parallelogram is 12 cm and its”

  1. [tex]\huge{\boxed{\boxed{\mathcal{\underline{\overline{\red{S{\green{o{\orange{l{\blue{u{\pink{t{\purple{i{\red{o{\blue{n}}}}}}}}}}}}}}}}}}}}}[/tex]

    Q3.

    [tex] \green{ \mathfrak{ \underbrace{formula}}}[/tex]

    Sum of the angles of the quadrilateral = 360°

    Let each angles of the quadrilateral be ∠a, ∠b, ∠c, ∠d

    i.e., ∠a + ∠b + ∠c + ∠d = 360°

    But, given that all the angles are equal

    Therefore, ∠a = ∠b = ∠c = ∠d

    Substitute ∠b, ∠c, ∠d in terms of ∠a

    This gives, ∠a + ∠a + ∠a + ∠a = 360

    4∠a = 360

    ∠a = 360/4

    ∠a = 90°

    Therefore, ∠a = ∠b = ∠c = ∠d = 90°

    [tex] \\ [/tex]

    Q4.

    [tex] \green{ \mathfrak{ \underbrace{formula}}}[/tex]

    Area of a parallelogram = ½ x base x height

    Base = 12 cm

    Height = 18 cm

    Area of a parallelogram = ½ x 12 x 18

    = 12 x 9 = 108 cm²

    [tex] \\ [/tex]

    Q5.

    [tex] \green{ \mathfrak{ \underbrace{formula}}}[/tex]

    Probability of an event = P(E) = No. of favorable outcomes/Total no. of outcomes

    Favourable outcomes = (1,4),(2,4),(3,4),(4,4)(5,4),(6,4),(4,1),(4,2),(4,3),(4,5),(4,6)

    No. of favorable outcomes = 11

    Outcomes =

    (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

    (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

    (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

    (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

    (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

    (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

    Total no. of outcomes = 36

    Probability of getting a 4 on fair dice = 11/36

    Reply

Leave a Comment