Q
Find the value of x if (x- 1) is
a factor of p(x) = 2x^2+nx+√2

Q
Find the value of x if (x- 1) is
a factor of p(x) = 2x^2+nx+√2

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Reagan

2 thoughts on “Q<br />Find the value of x if (x- 1) is<br />a factor of p(x) = 2x^2+nx+√2<br />​”

  1. Answer:

    Step-by-step explanation:

    so,x-1=0

    x=1

    now,p(1)=0

    ⇒2x²+nx+√2=0

    ⇒2×1²+n×1+√2=0

    ⇒2+n+√2=0

    ⇒n=-2-√2

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