Contact Style About

Q-6. Explain the action of dilute hydrochloric acid on the following with

chemical equation:
(i) Magnesium ribbon.

By Allison

Q-6. Explain the action of dilute hydrochloric acid on the following with

chemical equation:
(i) Magnesium ribbon.
(ii) Sodium hydroxide.
(iii) Crushed egg shells.​

About the author
Allison

Device used to change the resistance many times in the electric circuit) *
(Rodhes) (Riostat) (Ammeter)
(Volta Meter)​

let [tex]v_{1}[/tex]= [tex]\left[\begin{array}{ccc}8\\2\\-6\end{array}\right][/tex], and [tex]v_{2}[/tex][tex]\left[\begin{array}{

2 thoughts on “Q-6. Explain the action of dilute hydrochloric acid on the following with<br /><br />chemical equation:<br />(i) Magnesium ribbon.”

  2. Answer:

    hey here is your answer

    Explanation:

    (i) Hydrogen gas will be formed Mg(s) +2HCl (dil)→ MgCl2(aq) +H2(s)

    (ii) Sodium chloride and water will be formed NaOH +HCl→ NaCl +H2O

    (iii) Crushed egg shell are made up of CaCO3 Which reacts with HCl to give brisk effervescence due to CO2

    CaCO3(s) +2HCl→ CaCl2 +H2O +CO2

    Reply

Leave a Comment