Q-1 If one zero of the Quadratic Polynomial
[k-1]x²+k+t is 3, Find value of k.​

2 thoughts on “Q-1 If one zero of the Quadratic Polynomial<br />[k-1]x²+k+t is 3, Find value of k.​”

1. Given that P(x) = ( k -1 ) x² + kx + 1 = 0.

   → p( -3 ) = ( k – 1 ) (-3)² + k (-3) + 1 = 0.

   ⇒ ( k – 1 ) × 9 -3 k + 1 = 0.

   ⇒ 9k – 9 – 3k + 1 = 0.

   ⇒ 6k – 8 = 0.

   ⇒ 6k = 8.

   Therefore, k = 8/6 = 4/3

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2. Step-by-step explanation:

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