prove that the sum of eithey pair of
opposite angles of a cyclic quadrilateral
180°
​

1 thought on “prove that the sum of eithey pair of<br />opposite angles of a cyclic quadrilateral<br />180°<br />​”

1. Answer:

   Let ABCD be the quadrilateral and O be the centre of the circle

   angle BOD=2×angle BAD {angle subtended at the centre is twice the angle at the circumference]….(1)

   angle BOD reflex ,=2×angle BCD..(2)

   Add (1) and (2)

   BOD + reflex BOD= 2(angle A + angle C)

   360= 2( A+C)

   A + C =360/2=180

   Similarly you can do for angle B+D=180

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