√2 + √5 √2 value is 1.414.. √5 value is 2.236… 1.414..+2.236.. = 3.65.. it has a repeating decimal °°°° there fore it’s irrational number if it helps you drop a thanks Reply
Answer: Mark my answer as brainlist Step-by-step explanation: Prove that (root 2 + root 5 ) is irrational Given: √2+√5 We need to prove√2+√5 is an irrational number. Proof: Let us assume that √2+√5 is a rational number. A rational number can be written in the form of p/q where p,q are integers and q≠0 √2+√5 = p/q On squaring both sides we get, (√2+√5)² = (p/q)² √2²+√5²+2(√5)(√2) = p²/q² 2+5+2√10 = p²/q² 7+2√10 = p²/q² 2√10 = p²/q² – 7 √10 = (p²-7q²)/2q p,q are integers then (p²-7q²)/2q is a rational number. Then √10 is also a rational number. But this contradicts the fact that √10 is an irrational number. Our assumption is incorrect √2+√5 is an irrational number. Hence proved. Reply
√2 + √5
√2 value is 1.414..
√5 value is 2.236…
1.414..+2.236..
= 3.65..
it has a repeating decimal
°°°° there fore it’s irrational number
if it helps you drop a thanks
Answer:
Mark my answer as brainlist
Step-by-step explanation:
Prove that (root 2 + root 5 ) is irrational
Given: √2+√5
We need to prove√2+√5 is an irrational number.
Proof:
Let us assume that √2+√5 is a rational number.
A rational number can be written in the form of p/q where p,q are integers and q≠0
√2+√5 = p/q
On squaring both sides we get,
(√2+√5)² = (p/q)²
√2²+√5²+2(√5)(√2) = p²/q²
2+5+2√10 = p²/q²
7+2√10 = p²/q²
2√10 = p²/q² – 7
√10 = (p²-7q²)/2q
p,q are integers then (p²-7q²)/2q is a rational number.
Then √10 is also a rational number.
But this contradicts the fact that √10 is an irrational number.
Our assumption is incorrect
√2+√5 is an irrational number.
Hence proved.