Step-by-step explanation: Lhs= (cosec A -cot A)² =(1/sin A – cosA/ Sin A)² =(1-cos A /sin A)² =(1-cos A)²/(sin²A) since sin²A = 1- cos²A =(1-cos A)(1-cosA)/(1²-cos²A) we know that a²-b² = (a+b)(a-b) =(1-cos A)(1-cos A)/(1-cos A)(1+cos A) =1-cos A / 1+ cos A Reply
Step-by-step explanation:
Lhs= (cosec A -cot A)²
=(1/sin A – cosA/ Sin A)²
=(1-cos A /sin A)²
=(1-cos A)²/(sin²A)
since sin²A = 1- cos²A
=(1-cos A)(1-cosA)/(1²-cos²A)
we know that
a²-b² = (a+b)(a-b)
=(1-cos A)(1-cos A)/(1-cos A)(1+cos A)
=1-cos A / 1+ cos A