Preeti spent3/5of her money on a hand-bag. She spent the rest of the moneyon a dress and a belt. The hand-bag costs twice as much as the dress. The dresscosts ₹20 more than the belt. How much money did she have in the beginning? About the author Sadie
Answer: 100 rupees Step-by-step explanation: Total Cost=Rs x Handbag cost (H)=3/5x Cost of Dress (D)+ Belt (B)=x-3/5x=2/5x ie D+B=2/5x—(1) Handbag Cost=2 D Dress Cost= 20+ Belt (B) ie D=20+B ie D-B=20—(2) Handbag cost (H)=3/5x=2D D+B=2/5x—(1) D-B=20—(2) Add equation 1 & equation 2 D+B + D-B=2/5x+20 2D=2/5x+20 3/5x=2/5x+20 (substituting 2D=3/5X) 3/5x-2/5x=20 x/5=20 x=100 Total cost preeti had in the beginning =Rs 100 Handbag cost (H)=3/5x=3/5×100=Rs 60 Dress Cost = Rs 30 Belt Cost=Rs 10 Reply
so sorry so sorry so sorry so sorry so sorry
Answer:
100 rupees
Step-by-step explanation:
Total Cost=Rs x
Handbag cost (H)=3/5x
Cost of Dress (D)+ Belt (B)=x-3/5x=2/5x ie D+B=2/5x—(1)
Handbag Cost=2 D
Dress Cost= 20+ Belt (B) ie D=20+B ie D-B=20—(2)
Handbag cost (H)=3/5x=2D
D+B=2/5x—(1)
D-B=20—(2)
Add equation 1 & equation 2
D+B + D-B=2/5x+20
2D=2/5x+20
3/5x=2/5x+20 (substituting 2D=3/5X)
3/5x-2/5x=20
x/5=20
x=100
Total cost preeti had in the beginning =Rs 100
Handbag cost (H)=3/5x=3/5×100=Rs 60
Dress Cost = Rs 30
Belt Cost=Rs 10