point between the pillars and the height of each pillar.
33. All jacks, queens and kings are removed from a pack of 52 cards.

point between the pillars and the height of each pillar.
33. All jacks, queens and kings are removed from a pack of 52 cards. The remaining cards are well shuffled
and then a card is randomly drawn from it. Find the probability that this card is:
(i) a black face card
(ii) a red card
(iii) a black ace​

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1 thought on “point between the pillars and the height of each pillar.<br />33. All jacks, queens and kings are removed from a pack of 52 cards.”

  1. ⇒ Given:

    A deck of 52 cards with all the jacks, kings and queens removed.

    ⇒ To Find:

    The probability of randomly drawing:

    (i) a black face card

    (ii) a red card

    (iii) a black ace​

    from the rest of the cards.

    ⇒ Solution:

    ➡ The number of jacks in a deck = 4 [one each from spade, club, diamond and heart]

    ➡ The number of kings in a deck = 4 [one each from spade, club, diamond and heart]

    ➡ The number of queens in a deck = 4 [one each from spade, club, diamond and heart]

    Total number of cards removed = 4 x 3 = 12

    Remaining cards = 52 – 12 = 40 cards

    Now, solving the questions:

    (i) a black face card

    The black faced cards in the deck were the king, queen and the jack which were removed.

    Hence:

    [tex]\bf{\longrightarrow\:P(Outcome\:1)=0}[/tex]

    (ii) a red card

    The total number of red cards is 26 (13 x 2).

    From this, we need to subtract 6 cards – the three face cards from each set.

    That is:

    26 – 6 = 20

    [tex]\sf{P(Outcome\:2)=\dfrac{Favourable\:events}{Total\:events}}[/tex]

    [tex]\sf{P(Outcome\:2)=\dfrac{20}{40}}[/tex]

    [tex]\bf{\longrightarrow\:P(Outcomes\:2)=\dfrac{1}{2}}[/tex]

    (iii) a black ace

    No. of black ace cards = 2

    Total no. of cards = 40

    [tex]\sf{P(Outcome\:3)=\dfrac{Favourable\:events}{Total\:events}}[/tex]

    [tex]\sf{P(Outcome\:3)=\dfrac{2}{40}}[/tex]

    [tex]\bf{\longrightarrow\:P(Outcome\:3)=\dfrac{1}{20}}[/tex]

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