perimeter of rectangle whose length is 20/3 and 9/2breath please tell the answer I want to check​

2 thoughts on “perimeter of rectangle whose length is 20/3 and 9/2breath please tell the answer I want to check​”

1. Question:-

   What is the perimeter of the rectangle whose length is [tex] \frac{20}{3} [/tex]and breadth is [tex] \frac{9}{2} [/tex]

   Solution:-

   Given,

   Length of rectangle = [tex] \frac{20}{3} [/tex]

   Breadth of rectangle = [tex] \frac{9}{2} [/tex]

   We have,

   Perimeter of rectangle is 2(length+Breadth)

   So, Perimeter =

   [tex]2( \frac{20}{3} + \frac{9}{2} )[/tex]

   LCM = 2×3 = 6

   So,

   [tex]2 \times ( \frac{20 \times 2}{3 \times 2} + \frac{9 \times 3}{2 \times 3} ) [/tex]

   [tex]2 \times ( \frac{40}{6} + \frac{27}{6} )[/tex]

   [tex]2 \times ( \frac{40 + 27}{6} )[/tex]

   [tex]2 \times ( \frac{67}{6} )[/tex]

   [tex] = > \frac{67}{3} [/tex]

   Perimeter of rectangle is [tex] \frac{67}{3} [/tex] cm

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2. Answer:

   Perimeter of a rectangle= 2(l+b)

   So,

   2(20/3 + 9/2)

   2×67/6 = 67/2

   So, answer is 67/2

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