p(t)=t^2+3t−10
Find the value of the polynomial when t=−2

2 thoughts on “p(t)=t^2+3t−10<br /> Find the value of the polynomial when t=−2”

1. Answer:

   [tex]p(2) = {2}^{2} + 3 \times 2 – 10 \\ 2p = 2 \times 2 + 3 \times 2 – 10 \\ 2p = 4 + 6 – 10 \\ 2p = 10 – 10 \\ 2p = 0 \\ p = \frac{0}{2} = 0 \\ so \: \: \: p \: = 0[/tex]

   above is the equation

   hope it will help you dear friend

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2. Answer:

   -20

   Step-by-step explanation:

   put t=(-2)

   (-2)^2+ 3(-2)- 10

   4-6-10

   -20

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