*p²/4+p/3+ 1/9 हा विस्तार कोणत्या द्विपदीचा आहे?*

1️⃣ (p/2 + 1/3)²
2️⃣ (p/2 – 1/3)²
3️⃣ (p/4 + 1/9)²
4️

1 thought on “*p²/4+p/3+ 1/9 हा विस्तार कोणत्या द्विपदीचा आहे?*<br /><br />1️⃣ (p/2 + 1/3)²<br />2️⃣ (p/2 – 1/3)²<br />3️⃣ (p/4 + 1/9)²<br />4️”

1. [tex]\textbf{Given:}[/tex]

   [tex]\mathsf{\dfrac{p^2}{4}+\dfrac{p}{3}+\dfrac{1}{9}}[/tex]

   [tex]\textbf{To simplify:}[/tex]

   [tex]\mathsf{\dfrac{p^2}{4}+\dfrac{p}{3}+\dfrac{1}{9}}[/tex]

   [tex]\textbf{Solution:}[/tex]

   [tex]\textsf{Consider,}[/tex]

   [tex]\mathsf{\dfrac{p^2}{4}+\dfrac{p}{3}+\dfrac{1}{9}}[/tex]

   [tex]\textsf{This can be written as}[/tex]

   [tex]\mathsf{=\left(\dfrac{p}{2}\right)^2+\dfrac{p}{3}+\left(\dfrac{1}{3}\right)^2}[/tex]

   [tex]\mathsf{=\left(\dfrac{p}{2}\right)^2+2{\times}\dfrac{p}{2}{\times}\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2}[/tex]

   [tex]\mathsf{Using\;the\;identity,}[/tex]

   [tex]\boxed{\mathsf{(a+b)^2=a^2+2ab+b^2}}[/tex]

   [tex]\mathsf{=\left(\dfrac{p}{2}+\dfrac{1}{3}\right)^2}[/tex]

   [tex]\implies\boxed{\mathsf{\dfrac{p^2}{4}+\dfrac{p}{3}+\dfrac{1}{9}=\left(\dfrac{p}{2}+\dfrac{1}{3}\right)^2}}[/tex]

   [tex]\textbf{Answer:}[/tex]

   [tex]\mathsf{Option\;(1)\;is\;correct}[/tex]

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