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P(x) = x² + 3x²+3x+1
x+2 = 0
X = -2
P(-2) = (-23 +3/-22² + 300+1
9-2:-8+ 6 + 6 + 1
P(-2) = -8+0+1
P(

By Gabriella

P(x) = x² + 3x²+3x+1
x+2 = 0
X = -2
P(-2) = (-23 +3/-22² + 300+1
9-2:-8+ 6 + 6 + 1
P(-2) = -8+0+1
P(-2) = 7
Be Positive​

About the author
Gabriella

A rectangle has a width of 20 inches and a diagonal of 29 inches. Find the length of the rectangle​

Page No
Date:
6, 7, 8, 9,10} , A = { 118,5,7
SC7,8,91. Their
– Secot
) Prove that tano
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2 thoughts on “P(x) = x² + 3x²+3x+1<br />x+2 = 0<br />X = -2<br />P(-2) = (-23 +3/-22² + 300+1<br />9-2:-8+ 6 + 6 + 1<br />P(-2) = -8+0+1<br />P(”

  1. Step-by-step explanation:

    Dividing x

    3

    +3x

    2

    +3x+1 by 5+2x

    So, x

    3

    +3x

    2

    +3x+1 is dividend and 5+2x is divisor.

    Put, 5+2x=0

    ∴ x=

    2

    −5

    Let p(x)=x

    3

    +3x

    2

    +3x+1

    Putting x=

    2

    −5

    p(

    2

    −5

    )=(

    2

    −5

    )

    3

    +3(

    2

    −5

    )

    2

    +3(

    2

    −5

    )+1

    =

    8

    −125

    +

    4

    75

    −

    2

    15

    +1

    =

    8

    −125+150−60+8

    =

    8

    −27

    Thus, reminder of p(

    2

    −5

    )=

    8

    −27

    .

    ∴ We will get reminder as

    8

    −27

    when x

    3

    +3x

    2

    +3x+1 is divided by 5+2x

    Reply

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