Sin^2 60 +2tan45-cos^2 30 = 3.5Sin Step-by-step explanation: Given :Sin^2 60 +2tan45-cos^2 30Sin To Find : Find the value Solution : [tex]Sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex] [tex]Cos 30^{\circ}=\frac{\sqrt{3}}{2}[/tex] [tex]Tan 45^{\circ}[/tex] [tex]Sin^2 60^{\circ}=(\frac{\sqrt{3}}{2})^2=\frac{3}{4}[/tex] [tex]Cos^2 30^{\circ}=\frac{\sqrt{3}}{2}=\frac{3}{4}[/tex] [tex]Tan^2 45^{\circ}[/tex] [tex]Sin^2 60 +2tan45-cos^2 30Sin [/tex] [tex]\frac{3}{4}+2(1)+\frac{3}{4} [/tex] [tex]Hence Sin^2 60 +2tan45-cos^2 30 = 3.5Sin[/tex] #Learn more: Evaluate: tan30° + Sin? 60°-3Cos60° + – tan60°- 2tan45° https://brainly.in/question/14244241 Reply
Sin^2 60 +2tan45-cos^2 30 = 3.5Sin
Step-by-step explanation:
Given :Sin^2 60 +2tan45-cos^2 30Sin
To Find : Find the value
Solution :
[tex]Sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex]
[tex]Cos 30^{\circ}=\frac{\sqrt{3}}{2}[/tex]
[tex]Tan 45^{\circ}[/tex]
[tex]Sin^2 60^{\circ}=(\frac{\sqrt{3}}{2})^2=\frac{3}{4}[/tex]
[tex]Cos^2 30^{\circ}=\frac{\sqrt{3}}{2}=\frac{3}{4}[/tex]
[tex]Tan^2 45^{\circ}[/tex]
[tex]Sin^2 60 +2tan45-cos^2 30Sin [/tex]
[tex]\frac{3}{4}+2(1)+\frac{3}{4} [/tex]
[tex]Hence Sin^2 60 +2tan45-cos^2 30 = 3.5Sin[/tex]
#Learn more:
Evaluate:
tan30° + Sin? 60°-3Cos60° + – tan60°- 2tan45°
https://brainly.in/question/14244241