ons24. The diameter of a circle is increased by 15%the increase in the area of the circle is About the author Hailey
Step-by-step explanation: original circle: diameter= d area of original circle= π d^2 / 4 diameter is 15% increased new circle formed diameter of new circle=d(115) /100 = 23d/20 area of new circle= π (23d/20)^2 / 4 increase in area = new area-old area = π (23d/20)^2 / 4 – π (d)^2 / 4 = πd^/4(23^2-20^2)/20^2 = πd^/4(23^2-20^2)/20^2 =πd^/(129)/1600 = 129 πd^/1600 the increase in the area of the circle is 129 πd^/1600 Reply
Step-by-step explanation:
original circle:
diameter= d
area of original circle= π d^2 / 4
diameter is 15% increased new circle formed
diameter of new circle=d(115) /100
= 23d/20
area of new circle= π (23d/20)^2 / 4
increase in area = new area-old area
= π (23d/20)^2 / 4 – π (d)^2 / 4
= πd^/4(23^2-20^2)/20^2
= πd^/4(23^2-20^2)/20^2
=πd^/(129)/1600
= 129 πd^/1600
the increase in the area of the circle is 129 πd^/1600