one side of a right triangle measure 20m and the difference in length of its hypotenuse and the other side is 8 cm. find the length of its unknown side other than hypotenuse? About the author Lydia
Answer: Step-by-step explanation: let the hypotenuse be x so the remaining side will be x-8 according to question one side is 20 by pythagorus theorem we get h^2= b^2 +p^2 x^2=(x-800)^2 + 20^2 x^2=x^2+64-16x +400 {(a-b)^2= a^2+b^2+2ab} x^2-x^2+16x =464 x=464/16 x=29 so hypotenuse= x= 29 one side = x-8=21 and another side which is given is 20 Reply
Answer:
Step-by-step explanation:
let the hypotenuse be x
so the remaining side will be x-8
according to question one side is 20
by pythagorus theorem we get
h^2= b^2 +p^2
x^2=(x-800)^2 + 20^2
x^2=x^2+64-16x +400 {(a-b)^2= a^2+b^2+2ab}
x^2-x^2+16x =464
x=464/16
x=29
so hypotenuse= x= 29
one side = x-8=21
and another side which is given is 20