one person moving with 40km per one hour if his speed is increase 50 ℅ .how much time he take for 330 km About the author Gianna
Given, Speed (s1) = 40km/h Time (t1) = 15 mins = (15/60) hr Distance d1 = (s1 × t1) = 40 × (15/60) = 10 km WE KNOW THAT, Speed (s2) = 60 km/h Time (t2) = 15 min = (15/60) hour Distance (d2) = (s2 × t2) = 60 × (15/60) = 15 km Total distance (d) = (d1 + d2) = 10 km + 15 km = 25 km [tex]\mathcal { HOPE \: \: \: IT \: \: \: HELPS}[/tex] Reply
Answer: [tex] \huge\star \underline{ \boxed{ \purple{Answer}}}\star[/tex] Time taken to cover the distance of 330km = [tex]\sf{4\:hours\:12\:min’s}[/tex] Step-by-step explanation: Given :– s = 40km/hr d = 330 km and, speed increases by 50% To Find :– Time taken to cover 330 km. Solution :– ➝[tex]\sf{s_1}[/tex]= 40km/hr ➝t = 1 hr ➝d = ? ➝[tex]\sf{d\:=\:s_1\:\times\:t}[/tex] [tex]\sf\green{Putting\:values}[/tex] ➝[tex]\sf{d\:=\:40\:\times\:1}[/tex] ➝[tex]\sf{d\:=\:40\:km}[/tex] [tex]\sf\green{New\:Speed\::-}[/tex] ➝[tex]\sf{s_2\:=\:40\:\times\:\cancel\frac{100}{50}\:2}[/tex] ➝[tex]\sf\green{Now\:calculating\:time\:taken\:to\:cover\:330km\::-}[/tex] ➝[tex]\sf{d\:=\:330km}[/tex] ➝[tex]\sf{t\:=\:?}[/tex] ➝[tex]\sf{s_2\:=\:\frac{d}{t}}[/tex] ➝[tex]\sf{t\:=\:\frac{d}{s_2}}[/tex] ➝[tex]\sf{t\:=\:\cancel\frac{330}{80}\:4.12}[/tex] ➝[tex]\sf{t\:=\:4hr\:12min\:(approx.)}[/tex] [tex]\Large\sf\red{Hence,}[/tex] He will take 4 hr & 12 min to cover 330km. [tex]\huge\mathfrak\pink{Hope \: it \: helps \: you} [/tex] [tex]\huge\mathfrak\pink{friend} [/tex] Reply
Given,
Speed (s1) = 40km/h
Time (t1) = 15 mins = (15/60) hr
Distance d1 = (s1 × t1) = 40 × (15/60) = 10 km
WE KNOW THAT,
Speed (s2) = 60 km/h
Time (t2) = 15 min = (15/60) hour
Distance (d2) = (s2 × t2) = 60 × (15/60) = 15 km
Total distance (d) = (d1 + d2) = 10 km + 15 km = 25 km
[tex]\mathcal { HOPE \: \: \: IT \: \: \: HELPS}[/tex]
Answer:
[tex] \huge\star \underline{ \boxed{ \purple{Answer}}}\star[/tex]
Time taken to cover the distance of 330km =
[tex]\sf{4\:hours\:12\:min’s}[/tex]
Step-by-step explanation:
Given :–
s = 40km/hr
d = 330 km
and,
speed increases by 50%
To Find :–
Time taken to cover 330 km.
Solution :–
➝[tex]\sf{s_1}[/tex]= 40km/hr
➝t = 1 hr
➝d = ?
➝[tex]\sf{d\:=\:s_1\:\times\:t}[/tex]
[tex]\sf\green{Putting\:values}[/tex]
➝[tex]\sf{d\:=\:40\:\times\:1}[/tex]
➝[tex]\sf{d\:=\:40\:km}[/tex]
[tex]\sf\green{New\:Speed\::-}[/tex]
➝[tex]\sf{s_2\:=\:40\:\times\:\cancel\frac{100}{50}\:2}[/tex]
➝[tex]\sf\green{Now\:calculating\:time\:taken\:to\:cover\:330km\::-}[/tex]
➝[tex]\sf{d\:=\:330km}[/tex]
➝[tex]\sf{t\:=\:?}[/tex]
➝[tex]\sf{s_2\:=\:\frac{d}{t}}[/tex]
➝[tex]\sf{t\:=\:\frac{d}{s_2}}[/tex]
➝[tex]\sf{t\:=\:\cancel\frac{330}{80}\:4.12}[/tex]
➝[tex]\sf{t\:=\:4hr\:12min\:(approx.)}[/tex]
[tex]\Large\sf\red{Hence,}[/tex]
He will take 4 hr & 12 min to cover 330km.
[tex]\huge\mathfrak\pink{Hope \: it \: helps \: you} [/tex]
[tex]\huge\mathfrak\pink{friend} [/tex]