Answer: Here, the number of letters are 6 and every time we take 6 letters. Hence, required number of = ⌊6 = 6 × 5 × 4 × 3 × 2 × 1 = 720Read more on Sarthaks.com – https://www.sarthaks.com/731958/how-many-words-can-be-formed-using-letters-of-bhopal-a-124-b-240 Reply
Answer: Factorial Six Step-by-step explanation: No. of letters=6 Therefore, no. of permutations of the word ‘BHOPAL’= 6 P 6 = 6!/6-6! = 6!/0! = 6!(Since 0!=1) =6×5×4×3×2×1 = 720 Mark me brainliest, if it helped you! Reply
Answer:
Here, the number of letters are 6 and every time we take 6 letters. Hence, required number of = ⌊6 = 6 × 5 × 4 × 3 × 2 × 1 = 720Read more on Sarthaks.com – https://www.sarthaks.com/731958/how-many-words-can-be-formed-using-letters-of-bhopal-a-124-b-240
Answer:
Factorial Six
Step-by-step explanation:
No. of letters=6
Therefore, no. of permutations of the word
‘BHOPAL’= 6
P
6
= 6!/6-6!
= 6!/0!
= 6!(Since 0!=1)
=6×5×4×3×2×1
= 720
Mark me brainliest, if it helped you!