Number of moles of C obtained on reacting 20 moles of A with excess B by reaction:
2A+B =3C
If% yield of reaction is 80%

2 thoughts on “Number of moles of C obtained on reacting 20 moles of A with excess B by reaction:<br />2A+B =3C<br />If% yield of reaction is 80%”

1. Answer:

   2A + B —> 3C

   Since excess B is taken , we will consider A to be the limiting reagent.

   Now since 20 moles of A are taken , let us assume all 20 moles reacted (100% yield) and formed C.

   According to stoichiometry and comparing the coefficients of balanced equation:

   2 moles of A form 3 moles of C

   20 moles of A form 30 moles of C

   Assuming 100% theoretical yield , 30 moles of C are formed.

   But given % yield is 80%

   So actual moles of C obtained = 80% of 30 = 24 moles of C

   Ans is b. 24 moles

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2. Answer:

   d. 40 moles

   Explanation:

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