nu
Given n-1 :3
3
find
re
a (x3 –
3 – J
– 3
(
se ²+1
43
se z
2​

1 thought on “nu<br />Given n-1 :3<br />3<br />find<br />re<br />a (x3 –<br />3 – J<br />– 3<br />(<br />se ²+1<br />43<br />se z<br />2​”

1. Step-by-step explanation:

   nu

   Given n-1 :3

   3

   find

   re

   a (x3 –

   3 – J

   – 3

   (

   se ²+1

   43

   se z

   pls wite question in one line

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