My father’s age 5 years ago plus twice my age now gives 130. What is my father’s age? About the author Iris
let the father’s age be x father’s age 5 years ago = x-5 let your present age be y then your age 5 years ago= y-5 now according to question, =>x-5+2y=65 =>x+2y=70——-1 next =y-5+3x= 130 =3x+y=135——-2 ×2 subtracting 2 from 1 x+2y=. 70 6x+2y=.270 -. -. – ——————- -5x. =. -200 5x = 200 x=200/5 x= 40 so age of dad = x. = 40 y/o Reply
let the father’s age be x
father’s age 5 years ago = x-5
let your present age be y
then your age 5 years ago= y-5
now according to question,
=>x-5+2y=65
=>x+2y=70——-1
next
=y-5+3x= 130
=3x+y=135——-2 ×2
subtracting 2 from 1
x+2y=. 70
6x+2y=.270
-. -. –
——————-
-5x. =. -200
5x = 200
x=200/5
x= 40
so age of dad = x. = 40 y/o