Multiply (2m+ (-n)) by (-3m+ (-5)) and find the value of the product when m= 1 and n = -1 About the author Athena
Given We have given m= 1 & n=-1 To Find we have to find value of product [tex]\sf\huge\bold{\underline{\underline{{Solution}}}}[/tex] ⇢(2m+(-n) by (-3m+(-5)) First step is to solve values inside brackets. ⇢(2m-n) by (-3m-5) ⇢(2m-n)×(-3m-5) we have solved values inside brackets.Now, Multiply each and every values of first term with the second term. ⇢2m(-3m-5) -n(-3m-5) ⇢-6m²-10m+3mn+5n Now, we obtained the Equation Put m = 1 & n= -1 into equation ⇢-6(1)²-10(1)+3(1)(-1)+5(-1) ⇢6-10-3-5 ⇢-4-8 = -12 Hence,value of product is -12 Reply
[tex]\large\textsf{ }[/tex] [tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; QuEsTiOn :-}}[/tex] [tex]\large\textsf{ }[/tex] Multiply [ 2m+ (-n)] by [ -3m+ (-5)] and find the value of the product when m= 1 and n = -1 . [tex]\large\textsf{ }[/tex] [tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; GiVeN :-}}[/tex] [tex]\large\textsf{ }[/tex] The value of m = 1 and n = – 1 [tex]\large\textsf{ }[/tex] [tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; To FiNd :-}}[/tex] [tex]\large\textsf{ }[/tex] The value of the product = ? [tex]\large\textsf{ }[/tex] [tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; SoLuTiOn :-}}[/tex] [tex]\large\textsf{ }[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{[ 2m + ( – n ) ] × [ – 3m + ( – 5 ) ]}[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{( 2m – n ) × ( – 3m – 5 )}[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{2m ( 3m – 5 ) – n ( – 3m – 5 )}[/tex] [tex]\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{6m² – 10m + 3mn + 5n }}[/tex] [tex]\large\textsf{ }[/tex] Substituting the value of m = 1 and n = – 1 in the calculated Answer :- [tex]\large\textsf{ }[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{6m² – 10m + 3mn + 5n }[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{( 6 × 1² ) – ( 10 × 1 ) + ( 3 × 1 × – 1 ) + ( 5 × – 1 )}[/tex] [tex]\qquad\tt{:}\longrightarrow\large\textsf{6 – 10 – 3 – 5 }[/tex] [tex]\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{- 12 }}[/tex] [tex]\large\textsf{ }[/tex] [tex]\boxed{\large\textsf\textcolor{orange}{∴ The value of the product = – 12}}[/tex] [tex]\large\textsf{ }[/tex] Reply
Given
We have given m= 1 & n=-1
To Find
we have to find value of product
[tex]\sf\huge\bold{\underline{\underline{{Solution}}}}[/tex]
⇢(2m+(-n) by (-3m+(-5))
First step is to solve values inside brackets.
⇢(2m-n) by (-3m-5)
⇢(2m-n)×(-3m-5)
we have solved values inside brackets.Now, Multiply each and every values of first term with the second term.
⇢2m(-3m-5) -n(-3m-5)
⇢-6m²-10m+3mn+5n
Now, we obtained the Equation
Put m = 1 & n= -1 into equation
⇢-6(1)²-10(1)+3(1)(-1)+5(-1)
⇢6-10-3-5
⇢-4-8
= -12
Hence,value of product is -12
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[tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; QuEsTiOn :-}}[/tex]
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[tex]\large\textsf{ }[/tex]
[tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; GiVeN :-}}[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; To FiNd :-}}[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\LARGE\textsf{\underline\textcolor{aqua}{✯\; SoLuTiOn :-}}[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{[ 2m + ( – n ) ] × [ – 3m + ( – 5 ) ]}[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{( 2m – n ) × ( – 3m – 5 )}[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{2m ( 3m – 5 ) – n ( – 3m – 5 )}[/tex]
[tex]\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{6m² – 10m + 3mn + 5n }}[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{6m² – 10m + 3mn + 5n }[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{( 6 × 1² ) – ( 10 × 1 ) + ( 3 × 1 × – 1 ) + ( 5 × – 1 )}[/tex]
[tex]\qquad\tt{:}\longrightarrow\large\textsf{6 – 10 – 3 – 5 }[/tex]
[tex]\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{- 12 }}[/tex]
[tex]\large\textsf{ }[/tex]
[tex]\boxed{\large\textsf\textcolor{orange}{∴ The value of the product = – 12}}[/tex]
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