mother and her two sons get a room constructed for rupees 60000 the elder son contributes 3 by 8 of his mother’s contribution while the younger son contributes one by two of his mother’s share how much do the three contribute individually About the author Kylie
Answer: Step-by-step explanation: Lets assume Mother contribues ‘x’ then the eldest son contributes 3x/8 and the younget son contributes 1x/2 Total contribution = x + 3x/8 + 1x/2 =>8x/8 + 3x/8 + 4x/8 =>15x/8 now According To the Question 15x/8 = 60000 x/8 = 60000/15 = 4000 x = 4000*8 = 32000 ∴Mother contibutes = x = 32000 elder son contributes = 3x/8 = (3*32000)/8 = 1200 Younger son contributes = x/2 = 32000/2 = 16000 HOPE IT HELPS 🙂 Reply
Answer:
Step-by-step explanation:
Lets assume Mother contribues ‘x’
then the eldest son contributes 3x/8
and the younget son contributes 1x/2
Total contribution = x + 3x/8 + 1x/2
=>8x/8 + 3x/8 + 4x/8
=>15x/8
now According To the Question
15x/8 = 60000
x/8 = 60000/15 = 4000
x = 4000*8 = 32000
∴Mother contibutes = x = 32000
elder son contributes = 3x/8 = (3*32000)/8 = 1200
Younger son contributes = x/2 = 32000/2 = 16000
HOPE IT HELPS 🙂