Methane gas at 550 K and 5 bar undergoes a reversible adiabatic expansion to 1 bar. Assuming ideal gas state methane at these cond

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1. Answer:

   Using Gay Lussac’s Law,

   P1/T1=P2/T2

   5/550=1/T2

   5T2=550

   ∴Final Temperature T2=550/5

   =110 K

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