Answer: hey mate this is your ans Step-by-step explanation: Given y = xsin x Take log on both sides log y = sin x log x Differentiate w.r.t.x (1/y) × (dy/dx) = sin x × (1/x) + cos x log x dy/dx = y [(sin x)/x+ cos x log x ] = xsin x [(sin x)/x+ cos x log x ] = xsin x [x cos x log x + sin x]/x Reply
Answer:
hey mate this is your ans
Step-by-step explanation:
Given y = xsin x
Take log on both sides
log y = sin x log x
Differentiate w.r.t.x
(1/y) × (dy/dx) = sin x × (1/x) + cos x log x
dy/dx = y [(sin x)/x+ cos x log x ]
= xsin x [(sin x)/x+ cos x log x ]
= xsin x [x cos x log x + sin x]/x