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Manisha’s mothers is thrice the age of Manisha. After 4 years,
mother’s age would be two and a half times that of Manisha.
By Mia

Manisha’s mothers is thrice the age of Manisha. After 4 years,
mother’s age would be two and a half times that of Manisha.
Find their present ages.​

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Mia

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By Gauss’s elimination method for the equations x + 4y – 2 = -5;
x + y -62 = – 12; 3x – y-z = 4 elimination of x giv

1. Ascending:
Ascending: 3,0,
11
5 12
-12​

1 thought on “Manisha’s mothers is thrice the age of Manisha. After 4 years,<br />mother’s age would be two and a half times that of Manisha.<br”

  1. Answer:

    Manisha age = 12 years

    mother’s age = 36 years

    Step-by-step explanation:

    let the age of Manisha be x

    and mothers age will be 3x

    after 4 year’s Manisha age will be x + 4

    after 4 year’s mother’s age will be 3x + 4

    after 4 year’s mother’s age will be 2.5 time the age of Manisha

    [tex]3x + 4 = 2 \frac{1}{2} (x + 4) \\ 3x + 4 = \frac{5}{2} (x + 4) \\ 2(3x + 4) = 5(x + 4) \\ 6x + 8 = 5x + 20 \\ 6x – 5x = 20 – 8 \\ x = 12[/tex]

    therefore Manisha age = x = 12 years

    mother’s age = 3x = 3 × 12 = 36 years

    Hope you get your answer

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