log 64 to the base 2 under root 2 answer this question ❓ it’s urgent​

2 thoughts on “log 64 to the base 2 under root 2 answer this question ❓ it’s urgent​”

1. Answer: 12

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2. Answer:

   log 64 to the base sqrt(2)

   =log 64/log√2

   =log 2^6 / log 2^(1/2)

   =6 * log 2 / (1/2)* log 2

   =6 / (1/2)

   =6*2

   =12

   Step-by-step explanation:

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