Let f(x) = 2×2-5x, 1<x<3. The point c in (1,3)
given by the
Lagrange’s MVT for fis​

1 thought on “Let f(x) = 2×2-5x, 1<x<3. The point c in (1,3)<br />given by the<br />Lagrange’s MVT for fis​”

1. {f(3)-f(1)}/2=f'(c)

   3-(-3)/2=3

   4x-5=3

   x=2

   therefore c is 2

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