Length of base of a triangle is 2 more than its height if area is 48 squares form a quadratic equation to find the base and heigh

Length of base of a triangle is 2 more than its height if area is 48 squares form a quadratic equation to find the base and height ​

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1 thought on “Length of base of a triangle is 2 more than its height if area is 48 squares form a quadratic equation to find the base and heigh”

  1. Answer:

    Base = (4√6+1) cm

    Height = (4√6-1) cm

    Step-by-step explanation:

    Let the height be h

    Therefore, base = (h+2)

    Also, given that,

    Area = 48 cm sq.

    But, we know that,

    Area of triangle = ½ × base × height

    Substitute the respective values to get,

    => ½ × (h+2) × h = 48

    => h(h+2) = 48×2

    => h^2 + 2h = 96

    => h^2 + 2h – 96 = 0

    => h = {-2 ± √(2^2 -4(1)(-96))}/2(1)

    => h = (-2±√(4+382))/2

    => h = (-2±√386)/2

    => h = (-2±2√96)/2

    => h = -1±√96

    => h = -1±4√6

    But length can’t be negative.

    Therefore,

    => Height = -1+4√6 cm

    And

    => Base = 1+4√6 cm

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