Step-by-step explanation: Given zeros of polynomial are 3± 2 Let α,β be zeros of polynomial then α+β=3+ 2 +3− 2 =6 ________ (1) & αβ(3+ 2 )(3− 2 ) αβ=9−3 2 +3 2 −2=7 _________ (2) then quadratic equation is x 2 −(α+β)x+αβ=0 From (1) & (2) [x 2 −6x+7=0] solution Reply
Step-by-step explanation:
Given zeros of polynomial are 3±
2
Let α,β be zeros of polynomial
then
α+β=3+
2
+3−
2
=6 ________ (1)
& αβ(3+
2
)(3−
2
)
αβ=9−3
2
+3
2
−2=7 _________ (2)
then
quadratic equation is
x
2
−(α+β)x+αβ=0
From (1) & (2)
[x
2
−6x+7=0]
solution