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Jenny’s room is 13 feet long and 12 feet wide. Ruth’s room is 14 feet long and 11 feet wide. Whose room has the greater perimeter

By Iris

Jenny’s room is 13 feet long and 12 feet wide. Ruth’s room is 14 feet long and 11 feet wide. Whose room has the greater perimeter and greater area

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Iris


Prove that
tan A+secA-1
1+sin A
–

tanA-secA+1
COS A​

Give two concrete models for each geometric term. Put your answer in the empty column.
1.
point


2.

2 thoughts on “Jenny’s room is 13 feet long and 12 feet wide. Ruth’s room is 14 feet long and 11 feet wide. Whose room has the greater perimeter”

  1. Answer

    • Length of Jenny’s room, l = 13
    • breadth of Jenny’s room ,b = 12
    • Area of Jenny’s room = l × b

    Substitute the value we get

    [tex]:\implies[/tex] Area of Jenny’s room = 13 × 12

    [tex]:\implies[/tex] Area of Jenny’s room = 156 feet square.

    Now, Calculating the Perimeter of Jenny’s Room.

    • Perimeter of Jenny’s room = 2(l+b)

    Substitute the value we get

    [tex]:\implies[/tex] Perimeter of Jenny’s room =2(13+12)

    [tex]:\implies[/tex] Perimeter of Jenny’s room = 2(25)

    [tex]:\implies[/tex] Perimeter of Jenny’s room = 50 feet

    ___________________________________

    Now,

    • Length of Ruth’s room ,l = 14
    • breadth of Ruth’s room ,b = 11
    • Area of Ruth’s Room = l×b

    [tex]\longmapsto[/tex] Area of Ruth’s Room = 14×11

    [tex]\longmapsto[/tex] Area of Ruth’s Room =154 feet square

    And , Perimeter of Ruth’s Room

    • Perimeter of Ruth’s Room = 2(l+b)

    [tex]\longmapsto[/tex] Perimeter of Ruth’s Room =2(14+11)

    [tex]\longmapsto[/tex] Perimeter of Ruth’s Room = 2(25)

    [tex]\longmapsto[/tex] Perimeter of Ruth’s Room = 50 feet

    _______________________________

    Hence, Jenny’s room has greater area than Ruth’s room.

    Perimeter of both room is same .

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  2. Answer:

    Given :–

    Jenny’s room is 13 feet long and 12 feet wide. Ruth’s room is 14 feet long and 11 feet wide.

    To Find :–

    room has the greater perimeter and greater area

    Solution :–

    Perimeter of Jenny’s Room = 2(l + b)

    Perimeter = 2(13 + 12)

    Perimeter = 2(25)

    Perimeter = 50 m

    Area of Jenny’s Room = l × b

    Area = 13 × 12

    Area = 156 m²

    Now

    Perimeter of Ruth’s Room = 2(l + b)

    Perimeter = 2(14 + 11)

    Perimeter = 2(25)

    Perimeter = 50 m

    Area of Ruth’s Room = l × b

    Area = 14 × 11

    Area = 154 m²

    Therefore,

    • Perimeter are same
    • Area of Jenny’s Room is greater

    [tex] \\ [/tex]

    Reply

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