Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present
and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is 3
62.000, find the initial monthly salary of Vikas.
Answer:
Rs 24000
Step-by-step explanation:
Appropriate Question :-
Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is Rs 62, 000, find the initial monthly salary of Vikas.
Solution :-
It is given that
¤ The ratio between the present and initial monthly salary of Vikas is 5 : 4
☆ Let us assume that
Also,
It is given that
¤ The ratio between the present and initial monthly salary of Rohan is 8 : 7.
☆ Let us assume that
According to statement,
It is given that,
☆ Initial monthly salaries of Vikas and Rohan were in the ratio 6 : 7.
Therefore,
[tex]\rm :\longmapsto\:4x : 7y = 6 : 7[/tex]
[tex]\rm :\longmapsto\:\dfrac{4x}{7y} = \dfrac{6}{7} [/tex]
[tex]\rm :\longmapsto\:\dfrac{4x}{y} = \dfrac{6}{1} [/tex]
[tex]\bf\implies \:x = \dfrac{3y}{2} – – – (1)[/tex]
Also,
According to statement,
☆ Sum of their present salary is Rs 62000.
[tex]\rm :\longmapsto\:5x + 8y = 62000[/tex]
[tex]\rm :\longmapsto\:5 \times \dfrac{3y}{2} + 8y = 62000[/tex]
[tex]\rm :\longmapsto\:\dfrac{15y}{2} + 8y = 62000[/tex]
[tex]\rm :\longmapsto\:\dfrac{15y + 16y}{2}= 62000[/tex]
[tex]\rm :\longmapsto\:\dfrac{31y}{2}= 62000[/tex]
[tex]\rm :\longmapsto\:\dfrac{y}{2}= 2000[/tex]
[tex]\bf\implies \:y = 4000 – – – (2)[/tex]
☆ On substituting the value of y in equation (1), we get
[tex]\rm :\longmapsto\: \:x = \dfrac{3}{2} \times 2000[/tex]
[tex]\bf\implies \:x = 3000[/tex]
Hence,
Initial monthly salary of Vikas = 4x = 4 × 3000 = Rs 12000
Additional Information :-
[tex]\rm :\longmapsto\:If \: \dfrac{a}{b} = \dfrac{c}{d} , \: then[/tex]
[tex]\green{\boxed{ \bf{ \: \dfrac{a}{c} = \dfrac{b}{d} \: \: \: \: \: \: \: \: \: \: \: \{alternendo \} }}}[/tex]
[tex]\green{\boxed{ \bf{ \: \dfrac{b}{a} = \dfrac{d}{c} \: \: \: \: \: \: \: \: \: \: \: \{invertendo \} }}}[/tex]
[tex]\green{\boxed{ \bf{ \: \dfrac{a + b}{b} = \dfrac{c + d}{d} \: \: \: \: \: \: \: \: \: \: \: \{componendo \} }}}[/tex]
[tex]\green{\boxed{ \bf{ \: \dfrac{a – b}{b} = \dfrac{c – d}{d} \: \: \: \: \: \: \: \: \: \: \: \{dividendo \} }}}[/tex]
[tex]\green{\boxed{ \bf{ \: \dfrac{a}{b} = \dfrac{c}{d} = \dfrac{a + c}{b + d} \: \: \: \: \: \: \: \: \: \: \: \{addendo \} }}}[/tex]