Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present
and initial mo

Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present
and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is 3
62.000, find the initial monthly salary of Vikas.​

About the author
Athena

2 thoughts on “Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present<br />and initial mo”

  1. Appropriate Question :-

    Initial monthly salaries of Vikas and Rohan were in the ratio 6:7. The individual ratios between their present and initial monthly salaries are 5:4 and 8:7 respectively. If the sum of their present monthly salaries is Rs 62, 000, find the initial monthly salary of Vikas.

    Solution :-

    It is given that

    ¤ The ratio between the present and initial monthly salary of Vikas is 5 : 4

    ☆ Let us assume that

    • Present salary of Vikas is 5x
    • Initial salary of Vikas is 4x.

    Also,

    It is given that

    ¤ The ratio between the present and initial monthly salary of Rohan is 8 : 7.

    ☆ Let us assume that

    • Present salary of Rohan is 8y
    • Initial salary of Rohan is 7y.

    According to statement,

    It is given that,

    ☆ Initial monthly salaries of Vikas and Rohan were in the ratio 6 : 7.

    Therefore,

    [tex]\rm :\longmapsto\:4x : 7y = 6 : 7[/tex]

    [tex]\rm :\longmapsto\:\dfrac{4x}{7y} = \dfrac{6}{7} [/tex]

    [tex]\rm :\longmapsto\:\dfrac{4x}{y} = \dfrac{6}{1} [/tex]

    [tex]\bf\implies \:x = \dfrac{3y}{2} – – – (1)[/tex]

    Also,

    According to statement,

    ☆ Sum of their present salary is Rs 62000.

    [tex]\rm :\longmapsto\:5x + 8y = 62000[/tex]

    [tex]\rm :\longmapsto\:5 \times \dfrac{3y}{2} + 8y = 62000[/tex]

    [tex]\rm :\longmapsto\:\dfrac{15y}{2} + 8y = 62000[/tex]

    [tex]\rm :\longmapsto\:\dfrac{15y + 16y}{2}= 62000[/tex]

    [tex]\rm :\longmapsto\:\dfrac{31y}{2}= 62000[/tex]

    [tex]\rm :\longmapsto\:\dfrac{y}{2}= 2000[/tex]

    [tex]\bf\implies \:y = 4000 – – – (2)[/tex]

    ☆ On substituting the value of y in equation (1), we get

    [tex]\rm :\longmapsto\: \:x = \dfrac{3}{2} \times 2000[/tex]

    [tex]\bf\implies \:x = 3000[/tex]

    Hence,

    Initial monthly salary of Vikas = 4x = 4 × 3000 = Rs 12000

    Additional Information :-

    [tex]\rm :\longmapsto\:If \: \dfrac{a}{b} = \dfrac{c}{d} , \: then[/tex]

    [tex]\green{\boxed{ \bf{ \: \dfrac{a}{c} = \dfrac{b}{d} \: \: \: \: \: \: \: \: \: \: \: \{alternendo \} }}}[/tex]

    [tex]\green{\boxed{ \bf{ \: \dfrac{b}{a} = \dfrac{d}{c} \: \: \: \: \: \: \: \: \: \: \: \{invertendo \} }}}[/tex]

    [tex]\green{\boxed{ \bf{ \: \dfrac{a + b}{b} = \dfrac{c + d}{d} \: \: \: \: \: \: \: \: \: \: \: \{componendo \} }}}[/tex]

    [tex]\green{\boxed{ \bf{ \: \dfrac{a – b}{b} = \dfrac{c – d}{d} \: \: \: \: \: \: \: \: \: \: \: \{dividendo \} }}}[/tex]

    [tex]\green{\boxed{ \bf{ \: \dfrac{a}{b} = \dfrac{c}{d} = \dfrac{a + c}{b + d} \: \: \: \: \: \: \: \: \: \: \: \{addendo \} }}}[/tex]

    Reply

Leave a Comment