in trapezuim ABCD side AB parallel side CD diagonal AC and BD intersect at M prove that A(AMB ) /A(CMD) = AB2/CD2​

By Iris

in trapezuim ABCD side AB parallel side CD diagonal AC and BD intersect at M prove that A(AMB ) /A(CMD) = AB2/CD2​

About the author
Iris

1 thought on “in trapezuim ABCD side AB parallel side CD diagonal AC and BD intersect at M prove that A(AMB ) /A(CMD) = AB2/CD2​”

Leave a Comment