In the xy-plane, the positive x-intercept of the graph of the equation y =x -5 is a.

find a.

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1 thought on “In the xy-plane, the positive x-intercept of the graph of the equation y =x -5 is a.<br /><br />find a.<br /><br />​”

1. Answer:

   Answer

   Correct option is

   C

   y=2(x−3)2−2

   Choice A is not the correct answer. This answer displays the location of the y-value of the y-intercept of the graph (0,16) as a constant.

   Choice B is not the correct answer. This answer displays the location of the y-value of the y-intercept of the graph open parentheses (0,16) as a constant.

   Choice C is correct. The equation y=(2x−4)(x−4) can be written in vertex form, y=a(x−h)2+k to display the vertex,(h,k) of the parabola. To put the equation in vertex form, first multiply:

   (2x−4)(x−4)

   =2×2−8x−4x+16

   =2×2−12x+16=2(x2−6x+8)=0

   ⇒x2−2×3x+9−9+8=0

   ⇒(x−3)2−1=0

   ⇒x−3=±1

   ∴x=3±1=4,2

   y=0 for x=2,4

   Choice D is not the correct answer. This answer displays the location of the x-value of one of the x-intercepts of the graph (2,0) as a constant.

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