In the parallelogram ABCD
CA=65, find other angles of a square abcd

​

2 thoughts on “In the parallelogram ABCD<br />CA=65, find other angles of a square abcd<br /><br />​”

1. Answer:

   Let ABCD be a parallelogram in which ∠A=65

   ∘

   .

   Since AD∥BC we can treat AB as a transversal. So,

   ∠A+∠B=180

   ∘

   65

   +∠B=180

   ∘

   ∠B=180

   ∘

   −65

   ∘

   ∠B=115

   ∘

   Since the opposite angles of a parallelogram are equal, we have

   ∠C=∠A=65

   ∘

   and ∠D=∠B=115

   ∘

   Hence, ∠B=115

   ∘

   ,∠C=65

   ∘

   and ∠D=115

   ∘Please mark me brainlist

   Reply

2. Answer:

   answer mill gya hain na gg gg

   Reply