1 thought on “In the adjoining figure an isosceles triangle ABC with AB=AC circumscribes a circle. Prove that point of contact P bisect the base”
Step-by-step explanation:
Proof: AR and AQ are the tangents drawn from an external point A to the circle. Similarly, BR=BP and CP=CQ. It is given that in triangle ABC, AB=AC. ⇒ P bisects BC.
Step-by-step explanation:
Proof: AR and AQ are the tangents drawn from an external point A to the circle. Similarly, BR=BP and CP=CQ. It is given that in triangle ABC, AB=AC. ⇒ P bisects BC.