In standstill water a steam boat is accelerated 3 m per square from position of rest in an interval of 8 sec determine the distance travel by the boat within the interval About the author Kaylee
Given :- In standstill water a steam boat is accelerated 3 m per square from position of rest in an interval of 8 sec To Find :- Distance covered Solution :- We know that s = ut + 1/2 a t² s = (0)(8) + 1/2 × 3 × (8)² s = 0 + 1/2 × 3 × 64 s = 3/2 × 64 s = 3 × 32 s = 96 m[tex]\\[/tex] Reply
Given:– Acceleration ,a = 3m/s Initial velocity ,u = 0m/s Time taken ,t = 8s To Find:– Distance travel by the boat ,s Solution:– We have to calculate the distance covered by the boat in given time interval. Using 2nd equation of motion s = ut + 1/2at² where, v is the final velocity a is the acceleration u is the initial velocity t is the time taken s is the distance covered Substitute the value we get [tex]:\implies[/tex] s = 0×8 + 1/2×3 × 8² [tex]:\implies[/tex] s = 0 + 1/2 × 3 × 64 [tex]:\implies[/tex] s = 3/2 × 64 [tex]:\implies[/tex] s = 3 × 32 [tex]:\implies[/tex] s = 96 m Hence, the distance covered by the steam boat is 96 metres. Reply
Given :-
In standstill water a steam boat is accelerated 3 m per square from position of rest in an interval of 8 sec
To Find :-
Distance covered
Solution :-
We know that
s = ut + 1/2 a t²
s = (0)(8) + 1/2 × 3 × (8)²
s = 0 + 1/2 × 3 × 64
s = 3/2 × 64
s = 3 × 32
s = 96 m[tex]\\[/tex]
Given:–
To Find:–
Solution:–
We have to calculate the distance covered by the boat in given time interval. Using 2nd equation of motion
where,
Substitute the value we get
[tex]:\implies[/tex] s = 0×8 + 1/2×3 × 8²
[tex]:\implies[/tex] s = 0 + 1/2 × 3 × 64
[tex]:\implies[/tex] s = 3/2 × 64
[tex]:\implies[/tex] s = 3 × 32
[tex]:\implies[/tex] s = 96 m