In APQR, LPQR = 90° and the length of hypotenuse PR is 13 cm
Find PQ2 + QR2​

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1. Answer:

   CONSTRUCTION: Extend QS to ST , such that QS = ST

   Now, PTRQ is a parallelogram ( as its diagonals bisect each other)

   < PQR = 90° ( given)

   => PTRQ is a rectangle. ( //gm with an angle = 90° is rectangle)

   => PR = QT ( diagonals of rectangles are equal)

   => QS = PR/2

   => QS = 10/5 = 5 cm

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