In an A.P sum of three number in A.P is 24 product is 480 write three terms of an A.P About the author Charlotte
Answer: Let the three terms be a – d, a, a + d Sum = 24 Product = 480 ∴a−d+a+a+d=24 3a=24 ∴a=8 (a−d)(a)(a+d)=480 (8−d)(8)(8+d)=480[∵a=8] (8−d)(8+d)=60 64−d2=60 d2=±4=±2 If a=8,d=2 the terms are a−d=8−2=6,a=8,a+d=8+2=10 ∴ the term are 6,8,10. We will get the same values if we’ll consider d=−2. Reply
Answer:
Let the three terms be a – d, a, a + d
Sum = 24 Product = 480
∴a−d+a+a+d=24
3a=24
∴a=8
(a−d)(a)(a+d)=480
(8−d)(8)(8+d)=480[∵a=8]
(8−d)(8+d)=60
64−d2=60
d2=±4=±2
If a=8,d=2 the terms are
a−d=8−2=6,a=8,a+d=8+2=10
∴ the term are 6,8,10.
We will get the same values if we’ll consider d=−2.