In a factory 50 workers are employed the monthly salaries of 50 workers of a company are show in the table

2 thoughts on “In a factory 50 workers are employed the monthly salaries of 50 workers of a company are show in the table”

1. Solution :–

   Salary(in 1000) ——–Fi ——- Xi ——— FiXi —— CF

   12 – 14 ——————– 6 ——- 13 ———- 78 ——- 6

   14 – 16 ——————– 8 ——- 15 ———- 120 ——-14

   16 – 18 ——————–12 ——- 17 ———- 204 ——-26

   18 – 20 ——————–7 ——- 19 ———- 133 ——- 33

   20 – 22 ——————–9 ——-21 ———- 189 ——- 42

   22 – 24 ——————–8 ——- 23 ———-184 ——- 50

   ⅀Fi = 50 ⅀FiXi = 908

   so,

   → Mean salary = ⅀FiXi / ⅀Fi = 908000 / 50 = Rs.18,160 .

   now, Here , n = 50 .

   So,

   → (n/2) = 25.

   Then,

   • Cumulative frequency greater than 25 is 26, corresponds to the class 16 – 18.

   Therefore,

   → Class 16 – 18 is the median class.

   Now,

   • Median = l + [{(n/2) – cf} / f] * h

   from data we have :-

   • l = lower limit of median class = 16000
   • n = total frequency = 50
   • cf = Cumulative frequency of class before median class = 14
   • f = frequency of median class = 12 .
   • h = size of class = 2000 .

   Putting all value we get :-

   → Median = 16000 + [(25 – 14)/12] * 2000

   → Median = 16000 + (11/12) * 2000

   → Median = 16000 + 1833.34

   → Median = 17833.34 .

   now,

   → Probability of salary less than 16000 = 14/50 = (7/25) .

   → Probability of salary more than 16000 = 36/50 = (18/25) .

   → Number of workers having salary more than mean salary = 7 + 9 + 8 = 24 .

   Learn more :-

   find the median from the following wages distribution for a certain factory.

   https://brainly.in/question/38273562

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2. Answer:

   please see on meritnation or shaala app

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