In a binomial distribution, what are the values of n and p if variance= mean^2?

1 thought on “In a binomial distribution, what are the values of n and p if variance= mean^2?”

1. Answer:

   question is not clear to me but still check the answer below

   Step-by-step explanation:

   Variance of binomial distribution = np(1-p)

   mean of binomial distribution = np

   given variance = 2 x Mean

   it means

   np(1-p) = 2np

   1-p = 2

   so p = 3

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