In 1/√6-√3 = a√6 + b√3, find the value of a and b

a = 1/3 b= 1/3

a= √6 b = √3

a = √6/3 b= √3

Question

In 1/√6-√3 = a√6 + b√3, find the value of a and b  a = 1/3 b= 1/3  a= √6 b = √3  a = √6/3 b= √3​

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In 1/√6-√3 = a√6 + b√3, find the value of a and ba = 1/3 b= 1/3a= √6 b = √3a = √6/3 b= √3​