(iii) A bag contains 3 red, 3 white and 3 green balls of the same size. One ball istaken out of the bag at random, what is the probability that the ball picked upis (1) red (2) either white or green. About the author Arya
Answer: 1. 1/3 2. 2/3 Step-by-step explanation: 1. P( 1 red ball ) = no. of red balls total no. of balls = 3 / 9 = 1/3 2. P( 1 white or 1 green ) = 1 – P( 1 red ) [ P(A) = 1 – P( not A) ] = 1 – 1/3 = 2/3 Alternate method: 2. P( 1 white or 1 green ) = P( 1 white ) + P( 1 green ) = no. of white balls + no. of green balls total no. of balls total no. of balls = 1/3 + 1/3 = 2/3 Reply
Answer:
the probability is either white or green
Answer:
1. 1/3
2. 2/3
Step-by-step explanation:
1. P( 1 red ball ) = no. of red balls
total no. of balls
= 3 / 9
= 1/3
2. P( 1 white or 1 green ) = 1 – P( 1 red ) [ P(A) = 1 – P( not A) ]
= 1 – 1/3
= 2/3
Alternate method:
2. P( 1 white or 1 green ) = P( 1 white ) + P( 1 green )
= no. of white balls + no. of green balls
total no. of balls total no. of balls
= 1/3 + 1/3
= 2/3