ii) A converging mirror forms a real image of height 4 cm of an object of height 1 cm placed 20 cm away from the mirror.a) Calculate the image distance b) What is the focal length of the mirror? About the author Savannah
Answer: h2 = – 4 cm (real iamge) h1 = 1 cm u = – 20 cm (i) v = ? m = h2/h1 = – (v/u) ⇒ -4/1 = -(v/-20) ⇒ v = -80 cm Image forms in front of the concave mirror. (ii) f = ? 1/v + 1/u = 1/f 1/-80 + 1/-20 = 1/f 1/f = – (1/80) – 1/20 = (-1 – 4)/80 = – (5/80) f = – 16 cm Reply
Answer:
h2 = – 4 cm (real iamge)
h1 = 1 cm
u = – 20 cm
(i) v = ?
m = h2/h1 = – (v/u)
⇒ -4/1 = -(v/-20)
⇒ v = -80 cm
Image forms in front of the concave mirror.
(ii) f = ?
1/v + 1/u = 1/f
1/-80 + 1/-20 = 1/f
1/f = – (1/80) – 1/20 = (-1 – 4)/80 = – (5/80)
f = – 16 cm
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