Step-by-step explanation: = 5[ (x² + y²) + 4(x – y)] = 5 [(x + y)² – 2xy ] + 4(x – y)] = 5 [8²-2 × 15/4] + 4 × 7 = 5 [ 64 – 15/2 ] + 28 = 5 x 113/2+28 = 565/2 + 28 = (565 + 56 )/2 = 621/2. Reply
Answer: [tex]\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}[/tex] [tex]\implies[/tex] = 5[ (x² + y²) + 4(x – y)] = 5 [(x + y)² – 2xy ] + 4(x – y)] = 5 [8²-2 × 15/4] + 4 × 7 = 5 [ 64 – 15/2 ] + 28 = 5 x 113/2+28 = 565/2 + 28 = (565 + 56 )/2 = 621/2. Please Drop Some Thanks. Reply
Step-by-step explanation:
= 5[ (x² + y²) + 4(x – y)]
= 5 [(x + y)² – 2xy ] + 4(x – y)]
= 5 [8²-2 × 15/4] + 4 × 7
= 5 [ 64 – 15/2 ] + 28
= 5 x 113/2+28
= 565/2 + 28
= (565 + 56 )/2
= 621/2.
Answer:
[tex]\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}[/tex]
[tex]\implies[/tex]
= 5[ (x² + y²) + 4(x – y)]
= 5 [(x + y)² – 2xy ] + 4(x – y)]
= 5 [8²-2 × 15/4] + 4 × 7
= 5 [ 64 – 15/2 ] + 28
= 5 x 113/2+28
= 565/2 + 28
= (565 + 56 )/2
= 621/2.