If x + y = 5 and x²+ y² = 13, then x^6- y^6
equal ? assume x>y​

1 thought on “If x + y = 5 and x²+ y² = 13, then x^6- y^6<br />equal ? assume x>y​”

1. Step-by-step explanation:

   x−y=1 and x+y=5.x−y=1 and x+y=5.

   (x+y)2=x2+y2+2xy⟹13+(2×6)(x+y)2=x2+y2+2xy⟹13+(2×6)

   ⟹(x+y)2=25⟹(x+y)2=25

   ⟹x+y=5⟹x+y=5

   (x−y)2=x2+y2−2xy⟹13−(2×6)(x−y)2=x2+y2−2xy⟹13−(2×6)

   ⟹(x−y)2=1⟹(x−y)2=1

   ⟹x−y=1⟹x−y=1

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