Answer: Given Quadratic polynomial is x² + (a+1)x + b zeroes of the polynomial are 2 and -3 sum of the zeroes = \frac{a+1}{1} 1 a+1 = 2-3 a+1 = -1 a = -2 product of the zeroes = \frac{b}{1} 1 b = 2(-3) b = -6 Reply
Answer:
Given
Quadratic polynomial is x² + (a+1)x + b
zeroes of the polynomial are 2 and -3
sum of the zeroes = \frac{a+1}{1}
1
a+1
= 2-3
a+1 = -1
a = -2
product of the zeroes = \frac{b}{1}
1
b
= 2(-3)
b = -6